*f*(

*p*) = 20 is get the

*f*(

*p*) out of there:

*f*(

*x*) =

*x*+1,

so

*f*(*p*)=*p*+1Now let's work on solving for

*p*:

2(

*p*+1)=20*p*+1 = 10

*p*=9

We're not done yet, of course. The question asked us for

*f*(3*p*), which we can now rewrite as*f*(27). Just plug 27 into the function like we did with*p*before:*f*(27) = 27 + 1

*f*(27) = 28

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